ParseTableName
Récapitulatif
Parses a table name into its components (database, owner, table) depending on the workspace. ParseTableName returns a string containing the parsed table name, with the database name, owner name, and table name separated by commas. This workspace must be a personal, file, or ArcSDE geodatabase.
Syntaxe
ParseTableName (name, {workspace})
Paramètre | Explication | Type de données |
name |
Specifies which table will be parsed. | String |
workspace |
Specifies the workspace for fully qualifying the table name. The workspace must be a personal, file, or ArcSDE geodatabase. | String |
Type de données | Explication |
String |
Returns the table name parsed into its components (owner name, database name, table name) separated by commas. |
Exemple de code
ParseTableName example
Parse a table name into its components.
import arcpy from arcpy import env import os # Get the full name of the feature class and # set the workspace for parsing the name. # fc = arcpy.GetParameterAsText(0) env.workspace = os.path.dirname(fc) # Parse the feature class name into its components # fullName = arcpy.ParseTableName(os.path.basename(fc)) nameList = fullName.split(",") databaseName = nameList[0] ownerName = nameList[1] fcName = nameList[2] # Qualify the name of the feature class that will be appended to and set # the workspace using the administrator's connection. # env.workspace = "Database Connections/Trans_admin.sde" appendFCName = arcpy.ValidateTableName("common", "roads") try: if ownerName == "grace": arcpy.CalculateField(fullName, "AppendedBy", ownerName) arcpy.Append_management(fullName, appendFCName) elif ownerName == "reed": arcpy.CalculateField(fullName, "AppendedBy", ownerName) arcpy.Append_management(fullName, appendFCName) else: arcpy.AddError("Unknown owner of feature class. Not appended.") except: arcpy.AddError(arcpy.GetMessages(2))
Rubriques connexes
7/10/2012