ParseTableName

Zusammenfassung

Parses a table name into its components (database, owner, table) depending on the workspace. ParseTableName returns a string containing the parsed table name, with the database name, owner name, and table name separated by commas. This workspace must be a personal, file, or ArcSDE geodatabase.

Syntax

ParseTableName (name, {workspace})
ParameterErläuterungDatentyp
name

Specifies which table will be parsed.

String
workspace

Specifies the workspace for fully qualifying the table name. The workspace must be a personal, file, or ArcSDE geodatabase.

String
Rückgabewert
DatentypErläuterung
String

Returns the table name parsed into its components (owner name, database name, table name) separated by commas.

Codebeispiel

ParseTableName example

Parse a table name into its components.

import arcpy
from arcpy import env
import os

# Get the full name of the feature class and
#   set the workspace for parsing the name.
#
fc = arcpy.GetParameterAsText(0)
env.workspace = os.path.dirname(fc)

# Parse the feature class name into its components
#
fullName = arcpy.ParseTableName(os.path.basename(fc))
nameList = fullName.split(",")
databaseName = nameList[0]
ownerName = nameList[1]
fcName = nameList[2]

# Qualify the name of the feature class that will be appended to and set 
# the workspace using the administrator's connection.
#
env.workspace = "Database Connections/Trans_admin.sde"
appendFCName = arcpy.ValidateTableName("common", "roads")

try:
    if ownerName == "grace":
        arcpy.CalculateField(fullName, "AppendedBy", ownerName)
        arcpy.Append_management(fullName, appendFCName)
    elif ownerName == "reed":
        arcpy.CalculateField(fullName, "AppendedBy", ownerName)
        arcpy.Append_management(fullName, appendFCName)
    else:
        arcpy.AddError("Unknown owner of feature class.  Not appended.")
except:
    arcpy.AddError(arcpy.GetMessages(2))

Verwandte Themen


7/10/2012